1. The problem asks to determine if the function represented by the table is linear or nonlinear. 2. A function is linear if it can be expressed in the form $$y = mx + b$$ where $m$ and $b$ are constants, and the rate of change (slope) between any two points is constant. 3. Let's examine the table values: | x | y | |---|---| | -2 | 2 | | 3 | -5 | | 3 | 1 | | 3 | -1 | | 6 | 1 | | 3 | 3 | 4. Notice that for $x=3$, $y$ takes multiple different values: $-5$, $1$, $-1$, and $3$. This means the function assigns more than one output to the same input. 5. A function must assign exactly one output for each input. Since this is violated, the relation is not a function, and thus cannot be linear. 6. Therefore, the given relation is neither a function nor linear. Final answer: The relation is nonlinear because it is not a function (multiple $y$ values for the same $x$).