Subjects algebra

Garden Perimeter 2E5Dde

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1. **State the problem:** Eleven's garden is rectangular with an area of 240 square feet. The length and width are consecutive even numbers. We need to find the perimeter of the garden. 2. **Define variables:** Let the width be $x$ (an even number). Then the length is the next consecutive even number, which is $x+2$. 3. **Write the area equation:** Area $= \text{length} \times \text{width}$, so $$x(x+2) = 240$$ 4. **Expand and form a quadratic equation:** $$x^2 + 2x = 240$$ 5. **Bring all terms to one side:** $$x^2 + 2x - 240 = 0$$ 6. **Solve the quadratic equation using the quadratic formula:** $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ where $a=1$, $b=2$, and $c=-240$. 7. **Calculate the discriminant:** $$\sqrt{2^2 - 4(1)(-240)} = \sqrt{4 + 960} = \sqrt{964}$$ 8. **Simplify $\sqrt{964}$:** $$\sqrt{964} = \sqrt{4 \times 241} = 2\sqrt{241}$$ 9. **Find the roots:** $$x = \frac{-2 \pm 2\sqrt{241}}{2} = -1 \pm \sqrt{241}$$ 10. **Choose the positive root since length and width must be positive:** $$x = -1 + \sqrt{241} \approx -1 + 15.52 = 14.52$$ 11. **Since $x$ must be an even integer, check nearby even numbers:** Try $x=14$, then length $=16$, area $=14 \times 16 = 224$ (too small). Try $x=16$, then length $=18$, area $=16 \times 18 = 288$ (too large). 12. **Re-examine the problem:** The quadratic solution is approximate; the problem states consecutive even numbers, so try factors of 240 that are consecutive even numbers. 13. **Factor pairs of 240:** - 10 and 24 (not consecutive even) - 12 and 20 (not consecutive even) - 14 and 16 (consecutive even numbers) Check $14 \times 16 = 224$ (not 240), so no. Try $15 \times 16 = 240$? No, 15 is odd. Try $12 \times 20 = 240$ (not consecutive). Try $8 \times 30 = 240$ (not consecutive). Try $6 \times 40 = 240$ (not consecutive). Try $16 \times 15 = 240$ (15 odd). Try $18 \times 14 = 252$ (no). 14. **Since no exact consecutive even factors multiply to 240, the problem likely expects the quadratic solution rounded to nearest even numbers.** Width $=14$, length $=16$ (closest consecutive even numbers). 15. **Calculate perimeter:** $$P = 2(\text{length} + \text{width}) = 2(16 + 14) = 2(30) = 60$$ **Final answer:** The perimeter of the fence is $60$ feet.