1. Stating the problem: Find the greatest common divisor (GCD) of the given numbers.
2. Formula and rules: The GCD of two or more integers is the largest positive integer that divides each of the integers without leaving a remainder.
3. For part (a), find GCD of 130 and 195:
- Prime factorization of 130: $$130 = 2 \times 5 \times 13$$
- Prime factorization of 195: $$195 = 3 \times 5 \times 13$$
- Common prime factors: 5 and 13
- Multiply common factors: $$5 \times 13 = 65$$
- So, GCD(130, 195) = 65
4. For part (b), find GCD of 180, 216, and 288:
- Prime factorization of 180: $$180 = 2^2 \times 3^2 \times 5$$
- Prime factorization of 216: $$216 = 2^3 \times 3^3$$
- Prime factorization of 288: $$288 = 2^5 \times 3^2$$
- Common prime factors with minimum powers:
- For 2: minimum power is 2
- For 3: minimum power is 2
- For 5: not common to all three
- Multiply common factors with minimum powers: $$2^2 \times 3^2 = 4 \times 9 = 36$$
- So, GCD(180, 216, 288) = 36
Final answers:
- a. 65
- b. 36
Gcd Numbers
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