Subjects algebra

Gcf Fractions F799Db

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1. The problem is to find the Greatest Common Factor (GCF) of each pair of numbers given in the fractions. 2. The formula for GCF is the largest positive integer that divides two numbers without leaving a remainder. 3. We find the factors of each number, then identify the common factors, and select the greatest one. 4. For the fraction $\frac{8}{72}$: - Factors of 8: 1, 2, 4, 8 - Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72 - Common factors: 1, 2, 4, 8 - GCF: 8 5. For the fraction $\frac{15}{25}$: - Factors of 15: 1, 3, 5, 15 - Factors of 25: 1, 5, 25 - Common factors: 1, 5 - GCF: 5 6. For the fraction $\frac{24}{36}$: - Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24 - Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 - Common factors: 1, 2, 3, 4, 6, 12 - GCF: 12 7. For the fraction $\frac{40}{60}$: - Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40 - Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 - Common factors: 1, 2, 4, 5, 10, 20 - GCF: 20 8. For the fraction $\frac{35}{49}$: - Factors of 35: 1, 5, 7, 35 - Factors of 49: 1, 7, 49 - Common factors: 1, 7 - GCF: 7 9. Solutions: - $\frac{8}{72}$ simplifies to $\frac{1}{9}$ - $\frac{15}{25}$ simplifies to $\frac{3}{5}$ - $\frac{24}{36}$ simplifies to $\frac{2}{3}$ - $\frac{40}{60}$ simplifies to $\frac{2}{3}$ - $\frac{35}{49}$ simplifies to $\frac{5}{7}$