1. **State the problem:** We have a sequence defined by the recurrence relation $$C_{n+1} = 1.0062 \times C_n$$ with initial value $$C_0 = 12000$$.
2. **Formula used:** This is a geometric sequence where each term is obtained by multiplying the previous term by a constant ratio $$r = 1.0062$$.
3. **General term formula:** The $$n$$-th term of a geometric sequence is given by
$$
C_n = C_0 \times r^n
$$
where $$C_0$$ is the initial term and $$r$$ is the common ratio.
4. **Explanation:** Here, $$C_0 = 12000$$ and $$r = 1.0062$$, so
$$
C_n = 12000 \times (1.0062)^n
$$
This formula allows us to find the value of $$C_n$$ for any $$n$$.
5. **Example:** To find $$C_1$$,
$$
C_1 = 12000 \times (1.0062)^1 = 12000 \times 1.0062 = 12074.4
$$
6. **Summary:** The sequence grows by multiplying the previous term by 1.0062 each time, starting from 12000.
**Final answer:** $$C_n = 12000 \times (1.0062)^n$$
Geometric Sequence 290Ec6
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