1. The problem asks for the 6th term of a geometric sequence with the first few terms 1, 5, 25, ... 2. A geometric sequence has terms where each term is found by multiplying the previous term by a constant ratio $r$. 3. The formula for the $n$th term of a geometric sequence is $$a_n = a_1 \times r^{n-1}$$ where $a_1$ is the first term and $r$ is the common ratio. 4. From the given terms, $a_1 = 1$ and $a_2 = 5$, so the common ratio is $$r = \frac{a_2}{a_1} = \frac{5}{1} = 5$$ 5. To find the 6th term, substitute $n=6$, $a_1=1$, and $r=5$ into the formula: $$a_6 = 1 \times 5^{6-1} = 5^5$$ 6. Calculate $5^5$: $$5^5 = 5 \times 5 \times 5 \times 5 \times 5 = 3125$$ 7. Therefore, the 6th term of the sequence is 3125.