1. The problem states that the ratio (common ratio) of a geometric progression (G.P.) is given as \(\frac{25}{49}\). We have the second term as \(x + 5\).
2. Let's denote the first term of the G.P. by \(a\) and the common ratio by \(r = \frac{25}{49}\).
3. The second term of the G.P. is given by \(ar\). Therefore, \(ar = x + 5\).
4. To find \(x\), we rearrange to get \(x = ar - 5\).
5. The problem is ambiguous regarding the first term \(a\), so if we assume \(a = 1\) (which is common for finding \(x\)), then:
$$x = \frac{25}{49} - 5$$
6. Calculate \(x\):
$$x = \frac{25}{49} - \frac{245}{49} = \frac{25 - 245}{49} = \frac{-220}{49}$$
7. Thus, the value of \(x = -\frac{220}{49}\).
If another value of \(a\) is given, \(x\) will depend on it accordingly.
Gp Second Term
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