Subjects algebra

Gp Second Term

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1. The problem states that the ratio (common ratio) of a geometric progression (G.P.) is given as \(\frac{25}{49}\). We have the second term as \(x + 5\). 2. Let's denote the first term of the G.P. by \(a\) and the common ratio by \(r = \frac{25}{49}\). 3. The second term of the G.P. is given by \(ar\). Therefore, \(ar = x + 5\). 4. To find \(x\), we rearrange to get \(x = ar - 5\). 5. The problem is ambiguous regarding the first term \(a\), so if we assume \(a = 1\) (which is common for finding \(x\)), then: $$x = \frac{25}{49} - 5$$ 6. Calculate \(x\): $$x = \frac{25}{49} - \frac{245}{49} = \frac{25 - 245}{49} = \frac{-220}{49}$$ 7. Thus, the value of \(x = -\frac{220}{49}\). If another value of \(a\) is given, \(x\) will depend on it accordingly.