1. **State the problem:** We need to find the percentage of the grain's weight lost after drying, given the moisture content before and after drying. 2. **Define variables:** Let the initial total weight of the grain be $W$. The initial moisture content is 23%, so the dry matter content is $100\%-23\%=77\%$. 3. **Calculate dry matter weight:** The dry matter weight remains constant during drying, so dry matter weight = $0.77W$. 4. **After drying:** Moisture content is 12%, so dry matter content is $100\%-12\%=88\%$ of the new weight $W_{new}$. 5. **Set up equation:** Dry matter weight before drying equals dry matter weight after drying: $$0.77W = 0.88W_{new}$$ 6. **Solve for new weight:** $$W_{new} = \frac{0.77}{0.88}W \approx 0.875W$$ 7. **Calculate weight lost:** $$\text{Weight lost} = W - W_{new} = W - 0.875W = 0.125W$$ 8. **Calculate percentage weight lost:** $$\frac{0.125W}{W} \times 100\% = 12.5\%$$ **Final answer:** The grain lost approximately 12.5% of its weight after drying.