1. The problem is to write an equation for a graph that starts near the point $(5,0)$ on the x-axis and curves upward to the right.
2. This shape suggests a function that is defined for $x \geq 5$ and increases as $x$ increases. Common functions with this behavior include logarithmic functions shifted right or square root functions shifted right.
3. A square root function shifted right by 5 units has the form:
$$f(x) = \sqrt{x - 5}$$
This function is defined for $x \geq 5$ and starts at $(5,0)$.
4. A logarithmic function shifted right by 5 units has the form:
$$f(x) = \log(x - 5)$$
This function is also defined for $x > 5$ and increases slowly.
5. Since the curve starts near $(5,0)$ and curves upward like a square root, the best fit is:
$$f(x) = \sqrt{x - 5}$$
6. Therefore, the equation for the graph is:
$$f(x) = \sqrt{x - 5}$$
Graph Equation 0A5805
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