1. **State the problem:** We need to graph the inequality $$y \geq \frac{3}{2}x - 6$$ on a coordinate plane with x and y axes ranging from -10 to 10. 2. **Understand the inequality:** The inequality $$y \geq \frac{3}{2}x - 6$$ means we want to shade the region on or above the line $$y = \frac{3}{2}x - 6$$. 3. **Graph the boundary line:** The boundary line is $$y = \frac{3}{2}x - 6$$. - This is a straight line with slope $$m = \frac{3}{2}$$ and y-intercept $$b = -6$$. - Plot the y-intercept at (0, -6). - Use the slope to find another point: from (0, -6), go up 3 units and right 2 units to (2, -3). - Draw a solid line through these points because the inequality includes equality ($$\geq$$). 4. **Shade the solution region:** Since the inequality is $$y \geq \frac{3}{2}x - 6$$, shade the region above the line. 5. **Summary:** The graph consists of a solid line through points (0, -6) and (2, -3) with shading above the line.