1. The problem asks to identify the graph of the inequality $y < -x - 3$ in the standard $(x, y)$ coordinate plane. 2. The boundary line for this inequality is $y = -x - 3$. This is a line with slope $-1$ and $y$-intercept $-3$. 3. The line passes through points where $x=0$, $y=-3$ and where $y=0$, $x=-3$. 4. Since the inequality is $y < -x - 3$, the solution region is the area below this line. 5. Graph A shows a dashed line with negative slope passing through $(0, -3)$ and $(-3, 0)$, and the shaded region is below the line. 6. Graph B has a line passing through $(0, 3)$ and $(3, 0)$, which does not match the line $y = -x - 3$. 7. Graph C has a positive slope and shading above the line, so it does not match. 8. Graph D has a positive slope and shading below the line, so it does not match. 9. Therefore, the correct graph is Graph A. Final answer: Graph A