1. The problem asks to find the point where the graphs of $y=f(x)$ and $y=f(4x)$ intersect. 2. The intersection means the $x$-values satisfy $f(x) = f(4x)$. 3. From the graph, points are given as: - $A(-4,-1)$ - $B(-3,-3)$ - $C(-2,0)$ - $D(-1,1)$ - $E(0,-1)$ - $F(2,-2)$ - $G(4,1)$ 4. The graph shows the intersection at point $D$. 5. To verify, check if $f(x) = f(4x)$ at $x=-1$: - $f(-1) = 1$ - $f(4 imes -1) = f(-4) = -1$ 6. Since $f(-1) \neq f(-4)$, the intersection is not at $x=-1$. 7. The problem states the intersection is at approximately $(0.375, 1.5)$, which is near point $D$ but not exactly at $x=-1$. 8. The intersection point is where $x$ satisfies $f(x) = f(4x)$, and from the graph, this occurs near $x=0.375$. 9. Among the given points, only point $D$ is highlighted as the intersection. 10. Therefore, the graphs of $y=f(x)$ and $y=f(4x)$ intersect at point $D$. Final answer: The graphs intersect at point $D$.