1. **Problem Statement:** Graph the equation $3y + 15x = 30$ and find its slope and intercepts. 2. **Rewrite the equation in slope-intercept form:** The slope-intercept form is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. Start with the given equation: $$3y + 15x = 30$$ Subtract $15x$ from both sides: $$3y = -15x + 30$$ Divide both sides by 3: $$y = -5x + 10$$ 3. **Identify slope and intercepts:** - Slope $m = -5$ - Y-intercept $b = 10$ (point $(0,10)$) 4. **Find the x-intercept:** Set $y=0$ and solve for $x$: $$0 = -5x + 10$$ $$5x = 10$$ $$x = 2$$ So, x-intercept is at $(2,0)$. 5. **Interpretation:** The line crosses the y-axis at 10 and the x-axis at 2, and it slopes downward with slope $-5$. 6. **Summary:** The graph is a straight line with equation $y = -5x + 10$, slope $-5$, y-intercept $(0,10)$, and x-intercept $(2,0)$. You can plot these points and draw the line through them to visualize the graph.