1. The problem is to graph the line with slope 3 and y-intercept 2. 2. The formula for a line in slope-intercept form is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. Here, $m = 3$ and $b = 2$, so the equation is $$y = 3x + 2$$. 4. To graph this line, start at the y-intercept $(0, 2)$ on the y-axis. 5. From the y-intercept, use the slope to find another point. Since the slope is 3, it means rise over run is 3/1. 6. From $(0, 2)$, move up 3 units and right 1 unit to reach the point $(1, 5)$. 7. Plot the points $(0, 2)$ and $(1, 5)$ on the graph. 8. Draw a straight line through these points extending in both directions. This visually shows where to graph the line with slope 3 and y-intercept 2.