1. The problem is to graph the linear equation $$y = -\frac{1}{3}x - 3$$. 2. The formula for a linear equation in slope-intercept form is $$y = mx + b$$, where $m$ is the slope and $b$ is the y-intercept. 3. For the equation $$y = -\frac{1}{3}x - 3$$, the slope $m = -\frac{1}{3}$ and the y-intercept $b = -3$. 4. To graph, start at the y-intercept $(0, -3)$ on the coordinate plane. 5. Use the slope to find another point: slope $-\frac{1}{3}$ means go down 1 unit and right 3 units from the y-intercept. 6. Plot the second point at $(3, -4)$. 7. Draw a straight line through these two points to complete the graph of the equation. This completes the graphing of the first equation.