1. The problem is to graph a line using the zero point (0,0) and another point from a given table. 2. To graph a line, you need two points. One point is given as the origin (0,0). 3. The formula for the slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is: $$m=\frac{y_2-y_1}{x_2-x_1}$$ 4. Once you have the slope $m$, the equation of the line in slope-intercept form is: $$y=mx+b$$ where $b$ is the y-intercept. Since one point is (0,0), $b=0$. 5. Choose another point from the table (for example, $(x_2,y_2)$). Calculate the slope: $$m=\frac{y_2-0}{x_2-0}=\frac{y_2}{x_2}$$ 6. The line equation becomes: $$y=\frac{y_2}{x_2}x$$ 7. To graph, plot the points (0,0) and $(x_2,y_2)$ on the coordinate plane. 8. Draw a straight line through these two points. Since the exact second point from the table is not provided, the general method above applies. Final answer: The line passes through (0,0) and $(x_2,y_2)$ with equation $$y=\frac{y_2}{x_2}x$$.