1. The problem is to graph the linear function $w(x) = 0.6x + 2$. 2. This function is in slope-intercept form $w(x) = mx + b$, where $m = 0.6$ is the slope and $b = 2$ is the y-intercept. 3. The y-intercept is the point where the graph crosses the y-axis, which is at $(0, 2)$. 4. The slope $0.6$ means that for every increase of 1 in $x$, $w(x)$ increases by 0.6. 5. To plot the graph, start at $(0, 2)$ on the y-axis. 6. From $(0, 2)$, move 1 unit to the right (increase $x$ by 1) and 0.6 units up (increase $w(x)$ by 0.6) to get the next point $(1, 2.6)$. 7. Connect these points with a straight line extending across the coordinate plane. 8. The graph will cross the x-axis where $w(x) = 0$. Solve for $x$: $$0 = 0.6x + 2$$ $$0.6x = -2$$ $$x = \frac{-2}{0.6} = -\frac{10}{3} \approx -3.33$$ 9. So the x-intercept is approximately $(-3.33, 0)$. 10. The graph is a straight line passing through points $(0, 2)$ and $(-3.33, 0)$ with slope 0.6. Final answer: The graph of $w(x) = 0.6x + 2$ is a straight line with y-intercept 2 and slope 0.6, crossing the x-axis at approximately $-3.33$.