Subjects algebra

Graph Linear 0Feca6

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1. **State the problem:** We need to graph the linear equation $$y = 2x - 8$$ on a coordinate grid. 2. **Formula and rules:** The equation is in slope-intercept form $$y = mx + b$$ where $$m$$ is the slope and $$b$$ is the y-intercept. 3. **Identify slope and intercept:** Here, the slope $$m = 2$$ and the y-intercept $$b = -8$$. 4. **Plot the y-intercept:** The point where the line crosses the y-axis is at $$(0, -8)$$. 5. **Use the slope to find another point:** Slope $$2$$ means rise over run is $$\frac{2}{1}$$. From $$(0, -8)$$, move up 2 units and right 1 unit to get $$(1, -6)$$. 6. **Find the x-intercept:** Set $$y=0$$ and solve for $$x$$: $$ 0 = 2x - 8 $$ Add 8 to both sides: $$ 8 = 2x $$ Divide both sides by 2: $$ \cancel{2}x = \frac{8}{\cancel{2}} $$ $$ x = 4 $$ So the x-intercept is $$(4, 0)$$. 7. **Draw the line:** Connect points $$(0, -8)$$ and $$(4, 0)$$ with a straight line extending in both directions. This completes the graph of $$y = 2x - 8$$.