1. **State the problem:** Graph the linear equation $y = -\frac{2}{3}x - 16$. 2. **Formula and rules:** A linear equation in slope-intercept form is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. 3. **Identify slope and intercept:** Here, $m = -\frac{2}{3}$ and $b = -16$. 4. **Plot the y-intercept:** The point $(0, -16)$ is where the line crosses the y-axis. 5. **Use the slope to find another point:** Slope $-\frac{2}{3}$ means for every 3 units right, go 2 units down. 6. **Calculate second point:** From $(0, -16)$ move right 3 to $x=3$, down 2 to $y = -18$, so point $(3, -18)$. 7. **Draw the line:** Connect points $(0, -16)$ and $(3, -18)$ with a straight line using a ruler. 8. **Label the line:** This is line number 1 as per the problem. **Final answer:** The graph is a straight line passing through $(0, -16)$ and $(3, -18)$ with slope $-\frac{2}{3}$.