1. The problem is to graph the linear function $y=\frac{x}{7}-2$. 2. The formula is already given: $y=\frac{x}{7}-2$. This is a linear function in slope-intercept form $y=mx+b$, where $m=\frac{1}{7}$ is the slope and $b=-2$ is the y-intercept. 3. The slope $m=\frac{1}{7}$ means for every increase of 7 units in $x$, $y$ increases by 1 unit. 4. The y-intercept $b=-2$ means the graph crosses the y-axis at the point $(0,-2)$. 5. To graph, start at $(0,-2)$ on the y-axis. 6. From there, move 7 units to the right (positive $x$ direction) and 1 unit up (positive $y$ direction) to plot another point. 7. Draw a straight line through these points extending in both directions. 8. The x-intercept can be found by setting $y=0$: $$0=\frac{x}{7}-2 \implies \frac{x}{7}=2 \implies x=14$$ So the graph crosses the x-axis at $(14,0)$. This completes the graphing of $y=\frac{x}{7}-2$.