1. The problem asks to graph the lines: $y=3x$, $y=4$, and $x=2$. 2. The line $y=3x$ is a linear function with slope 3 and passes through the origin $(0,0)$. 3. The line $y=4$ is a horizontal line crossing the y-axis at 4. 4. The line $x=2$ is a vertical line crossing the x-axis at 2. 5. To graph $y=3x$, plot points such as $(-1,-3)$ and $(3,9)$ and draw a straight line through them. 6. For $y=4$, draw a horizontal line parallel to the x-axis passing through $y=4$. 7. For $x=2$, draw a vertical line parallel to the y-axis passing through $x=2$. These lines intersect at points where their equations meet, for example, $y=3x$ and $x=2$ intersect at $(2,6)$. Final answer: The graph consists of a blue line $y=3x$, a horizontal line $y=4$, and a vertical line $x=2$ as described.