Let's graph the function $y = x^2 - 4$ step by step. Step 1: This is a parabola that opens upwards because of $x^2$. Step 2: The $-4$ moves the graph down 4 units. Step 3: The vertex (lowest point) is at $(0, -4)$. Step 4: To find x-intercepts, set $y=0$: $$0 = x^2 - 4$$ $$x^2 = 4$$ $$x = \pm 2$$ So, x-intercepts are $(2,0)$ and $(-2,0)$. Step 5: The y-intercept is when $x=0$: $$y = 0^2 - 4 = -4$$ So, y-intercept is $(0,-4)$. Final answer: The graph is a parabola with vertex at $(0,-4)$, x-intercepts at $(2,0)$ and $(-2,0)$, and y-intercept at $(0,-4)$.