1. The problem is to graph the function $y = x^2$. 2. The formula used is $y = x^2$, which is a quadratic function representing a parabola. 3. Important rules: - The graph is symmetric about the y-axis. - The vertex is at the origin $(0,0)$. - The parabola opens upwards. 4. To plot points, substitute values of $x$ and calculate $y$: - For $x = -2$, $y = (-2)^2 = 4$ - For $x = -1$, $y = (-1)^2 = 1$ - For $x = 0$, $y = 0^2 = 0$ - For $x = 1$, $y = 1^2 = 1$ - For $x = 2$, $y = 2^2 = 4$ 5. Plot these points and draw a smooth curve through them to form the parabola. Final answer: The graph of $y = x^2$ is a parabola opening upwards with vertex at $(0,0)$.