1. The problem is to graph the function $y = x^2$.
2. The formula used is $y = x^2$, which is a quadratic function representing a parabola.
3. Important rules:
- The graph is symmetric about the y-axis because $x^2$ is an even function.
- The vertex of the parabola is at the origin $(0,0)$.
- As $x$ increases or decreases, $y$ increases quadratically.
4. Intermediate work:
- Calculate some points: For $x = -2$, $y = (-2)^2 = 4$.
- For $x = -1$, $y = (-1)^2 = 1$.
- For $x = 0$, $y = 0^2 = 0$.
- For $x = 1$, $y = 1^2 = 1$.
- For $x = 2$, $y = 2^2 = 4$.
5. Plot these points and connect them smoothly to form a U-shaped curve.
6. The final graph is a parabola opening upwards with vertex at the origin.
Graph Quadratic 742331
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