1. The problem asks to describe the transformations applied to the graph of $y=f(x)$ to obtain each new function.
2. Recall the general transformation rules:
- Multiplying $f(x)$ by a constant $a$ vertically stretches ($|a|>1$) or compresses ($0<|a|<1$) the graph.
- Adding/subtracting a constant outside $f(x)$ shifts the graph vertically.
- Replacing $x$ by $x-h$ shifts the graph horizontally by $h$ units to the right if $h>0$, left if $h<0$.
- Multiplying $x$ by a constant inside $f(ax)$ compresses ($|a|>1$) or stretches ($0<|a|<1$) the graph horizontally.
- A negative sign outside $f(x)$ reflects the graph about the x-axis.
- A negative sign inside $f(-x)$ reflects the graph about the y-axis.
3. Now, analyze each function:
a) $y=3f(x)-1$
- Multiply $f(x)$ by 3: vertical stretch by factor 3.
- Subtract 1: shift graph down by 1 unit.
b) $y=f(x-2)+3$
- Replace $x$ by $x-2$: shift graph right by 2 units.
- Add 3: shift graph up by 3 units.
c) $y=f(2x)-5$
- Replace $x$ by $2x$: horizontal compression by factor $\frac{1}{2}$.
- Subtract 5: shift graph down by 5 units.
d) $y=-f(\frac{1}{2}x)-2$
- Replace $x$ by $\frac{1}{2}x$: horizontal stretch by factor 2.
- Multiply $f$ by -1: reflect graph about x-axis.
- Subtract 2: shift graph down by 2 units.
e) $y=\frac{2}{3}f(x+3)+1$
- Replace $x$ by $x+3$: shift graph left by 3 units.
- Multiply $f$ by $\frac{2}{3}$: vertical compression by factor $\frac{2}{3}$.
- Add 1: shift graph up by 1 unit.
f) $y=4f(-x)-4$
- Replace $x$ by $-x$: reflect graph about y-axis.
- Multiply $f$ by 4: vertical stretch by factor 4.
- Subtract 4: shift graph down by 4 units.
Final answers summarize the transformations for each part.
Graph Transformations 2Fbac1
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