1. **State the problem:** Graph the two linear equations on the same coordinate plane: a) $2x + y = 2$ b) $2x + y = 8$ 2. **Formula and rules:** Each equation represents a straight line. To graph, solve each for $y$ in terms of $x$: $$y = -2x + 2$$ $$y = -2x + 8$$ 3. **Intermediate work:** For equation a): $$2x + y = 2 \Rightarrow y = 2 - 2x$$ For equation b): $$2x + y = 8 \Rightarrow y = 8 - 2x$$ 4. **Explanation:** Both lines have the same slope $-2$, so they are parallel. - Line a) crosses the y-axis at $(0,2)$. - Line b) crosses the y-axis at $(0,8)$. 5. **Plot points:** For line a): - When $x=0$, $y=2$. - When $x=1$, $y=2 - 2(1) = 0$. For line b): - When $x=0$, $y=8$. - When $x=1$, $y=8 - 2(1) = 6$. 6. **Final answer:** The graph shows two parallel lines with slope $-2$, one crossing the y-axis at 2 and the other at 8.