1. **Stating the problem:** We are given two relations: - $y = 30 - 2x$ - $y = 2(x^2 + 2)$ We need to: (a) Draw the graphs of these two functions. (b) Find the values of $y$ for given $x$ values in the second relation. 2. **Understanding the functions:** - The first function is linear: $y = 30 - 2x$. - The second function is quadratic: $y = 2(x^2 + 2) = 2x^2 + 4$. 3. **Finding $y$ for given $x$ values in the quadratic function:** (a) When $x = 5$: $$y = 2(5^2 + 2) = 2(25 + 2) = 2 \times 27 = 54$$ (b) When $x = 8$: $$y = 2(8^2 + 2) = 2(64 + 2) = 2 \times 66 = 132$$ 4. **Summary:** - For $x=5$, $y=54$. - For $x=8$, $y=132$. These values can be plotted on the graph of $y = 2(x^2 + 2)$.