Let's draw the graph of the function $y = x^3 + x^2$ step by step! Step 1: Write the function: $y = x^3 + x^2$ Step 2: Find the $x$-intercepts. These are points where $y=0$. Set $x^3 + x^2 = 0$ Factor out $x^2$: $x^2(x + 1) = 0$ So, $x^2=0$ or $x+1=0$ That means $x=0$ or $x=-1$ So, $x$-intercepts are $(0, 0)$ and $(-1, 0)$ Step 3: Find the $y$-intercept. This is when $x=0$. Plug $x=0$ into $y = 0^3 + 0^2 = 0$ So, $y$-intercept is $(0, 0)$ The graph crosses the origin and the point $(-1, 0)$ on the $x$-axis. Final answer: The function is $y = x^3 + x^2$, with $x$-intercepts at $(0,0)$ and $(-1,0)$, and $y$-intercept at $(0,0)$. Great job! Keep up the good work!