1. **State the problem:** Solve the system of equations by graphing: $$y = x + 3$$ $$y = \frac{2}{5}x$$ 2. **Formula and rules:** The solution to a system of equations is the point(s) where the graphs intersect. 3. **Graph each equation:** - For $$y = x + 3$$, the y-intercept is 3 and the slope is 1. - For $$y = \frac{2}{5}x$$, the y-intercept is 0 and the slope is $$\frac{2}{5}$$. 4. **Find the intersection algebraically:** Set the right sides equal: $$x + 3 = \frac{2}{5}x$$ 5. **Solve for $$x$$:** $$x + 3 = \frac{2}{5}x$$ $$x - \frac{2}{5}x = -3$$ $$\frac{5}{5}x - \frac{2}{5}x = -3$$ $$\frac{3}{5}x = -3$$ 6. **Isolate $$x$$:** $$x = -3 \times \frac{5}{3}$$ $$x = -5$$ 7. **Find $$y$$ by substituting $$x = -5$$ into one equation:** Using $$y = x + 3$$: $$y = -5 + 3 = -2$$ 8. **Solution:** The graphs intersect at $$(-5, -2)$$. **Final answer:** $$\boxed{(-5, -2)}$$