1. **Problem statement:** We are given quantities of hair colour, colour developer, conditioner, and thickener, and we need to find and simplify ratios as fractions.
2. **Recall:** A ratio compares two quantities and can be expressed as a fraction. To simplify, divide numerator and denominator by their greatest common divisor (GCD).
3. **Part a:** Ratio of hair colour to thickener.
Given: hair colour = 20 mL, thickener = 3 mL.
Ratio = $\frac{20}{3}$.
Since 20 and 3 have no common factors other than 1, the ratio in simplest form is $\frac{20}{3}$.
4. **Part b:** Ratio of thickener to conditioner.
Given: thickener = 3 mL, conditioner = 15 mL.
Ratio = $\frac{3}{15}$.
Simplify by dividing numerator and denominator by 3:
$$\frac{\cancel{3}}{\cancel{15}} = \frac{1}{5}$$
5. **Part c:** Ratio of customer price to actual cost.
Given: customer price = 68, actual cost = 14.20.
Express 14.20 as fraction: $14.20 = \frac{1420}{100}$.
Ratio = $\frac{68}{14.20} = \frac{68}{\frac{1420}{100}} = 68 \times \frac{100}{1420} = \frac{6800}{1420}$.
Simplify numerator and denominator by dividing by 20:
$$\frac{\cancel{6800}^{340}}{\cancel{1420}^{71}} = \frac{340}{71}$$
340 and 71 share no common factors other than 1, so ratio in simplest form is $\frac{340}{71}$.
**Final answers:**
a. $\frac{20}{3}$
b. $\frac{1}{5}$
c. $\frac{340}{71}$
Hair Colour Ratios 30Cc66
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.