Subjects algebra

Hex Multiplication

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1. The problem is to multiply the hexadecimal numbers 1B0D8 and 9A. 2. Convert each hexadecimal number to decimal for easier multiplication. - $1B0D8_{16} = 1 \times 16^4 + 11 \times 16^3 + 0 \times 16^2 + 13 \times 16^1 + 8 \times 16^0$ - Calculate powers of 16: $16^4=65536$, $16^3=4096$, $16^2=256$, $16^1=16$, $16^0=1$ - Substitute: $1 \times 65536 + 11 \times 4096 + 0 + 13 \times 16 + 8 = 65536 + 45056 + 0 + 208 + 8 = 110808$ 3. Convert $9A_{16}$ to decimal: - $9 \times 16^1 + 10 \times 16^0 = 9 \times 16 + 10 = 144 + 10 = 154$ 4. Multiply the decimal equivalents: - $110808 \times 154 = 17064632$ 5. Convert the product back to hexadecimal: - Divide 17064632 by 16 repeatedly and record remainders: - $17064632 \div 16 = 1066539$ remainder $8$ - $1066539 \div 16 = 66658$ remainder $11$ (B) - $66658 \div 16 = 4166$ remainder $2$ - $4166 \div 16 = 260$ remainder $6$ - $260 \div 16 = 16$ remainder $4$ - $16 \div 16 = 1$ remainder $0$ - $1 \div 16 = 0$ remainder $1$ - Reading remainders from last to first: $1 0 4 6 2 B 8$ - So, $17064632_{10} = 10462B8_{16}$ Final answer: $1B0D8_{16} \times 9A_{16} = 10462B8_{16}$