1. The problem is to multiply the two hexadecimal numbers $\text{ab1b6}$ and $\text{eb6b5b4}$ and then convert the result to decimal. 2. First, convert each hexadecimal number to decimal. $\text{ab1b6}_{16} = 10 \times 16^4 + 11 \times 16^3 + 1 \times 16^2 + 11 \times 16^1 + 6 \times 16^0$ Calculate powers of 16: $16^4 = 65536$, $16^3 = 4096$, $16^2 = 256$, $16^1 = 16$, $16^0 = 1$ So, $\text{ab1b6}_{16} = 10 \times 65536 + 11 \times 4096 + 1 \times 256 + 11 \times 16 + 6 \times 1$ $= 655360 + 45056 + 256 + 176 + 6 = 701854$ 3. Similarly, convert $\text{eb6b5b4}_{16}$: Digits: e=14, b=11, 6=6, b=11, 5=5, b=11, 4=4 Positions (right to left): 6,5,4,3,2,1,0 Calculate: $14 \times 16^6 + 11 \times 16^5 + 6 \times 16^4 + 11 \times 16^3 + 5 \times 16^2 + 11 \times 16^1 + 4 \times 16^0$ Calculate powers: $16^6=16777216$, $16^5=1048576$, $16^4=65536$, $16^3=4096$, $16^2=256$, $16^1=16$, $16^0=1$ Calculate each term: $14 \times 16777216 = 234881024$ $11 \times 1048576 = 11534336$ $6 \times 65536 = 393216$ $11 \times 4096 = 45056$ $5 \times 256 = 1280$ $11 \times 16 = 176$ $4 \times 1 = 4$ Sum all: $234881024 + 11534336 + 393216 + 45056 + 1280 + 176 + 4 = 246660092$ 4. Now multiply the two decimal numbers: $701854 \times 246660092$ 5. Perform the multiplication: $701854 \times 246660092 = 173099091091768$ 6. Therefore, the product of $\text{ab1b6}_{16}$ and $\text{eb6b5b4}_{16}$ in decimal is $173099091091768$. Final answer: $$173099091091768$$