1. The problem asks for the equation of a line with slope 0 passing through the point $(5,-16)$. 2. Recall the slope-intercept form of a line is given by $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. Since the slope $m=0$, the equation simplifies to $$y = b$$. This means the line is horizontal. 4. To find $b$, substitute the point $(5,-16)$ into the equation: $$-16 = b$$. 5. Therefore, the equation of the line is $$y = -16$$. This is the simplest form and uses integers as required.