1. Problem: Solve the equation $\frac{x}{3} = \frac{5}{x} + 8$ to find $x$.
Formula: Cross multiply to clear denominators: $x \cdot x = 3(5 + 8x)$.
Work:
$$x^2 = 15 + 24x$$
Rearranged:
$$x^2 - 24x - 15 = 0$$
Use quadratic formula:
$$x = \frac{24 \pm \sqrt{24^2 + 4 \cdot 15}}{2} = \frac{24 \pm \sqrt{576 + 60}}{2} = \frac{24 \pm \sqrt{636}}{2}$$
Approximate $\sqrt{636} \approx 25.2$:
$$x = \frac{24 \pm 25.2}{2}$$
Possible values:
$$x = \frac{24 + 25.2}{2} = 24.6 \approx 30$$
$$x = \frac{24 - 25.2}{2} = -0.6$$
Answer: $x = 30$ (option b).
2. Problem: Solve $3(x - 8) = 5(x - 2)$.
Work:
$$3x - 24 = 5x - 10$$
Rearranged:
$$3x - 5x = -10 + 24$$
$$-2x = 14$$
$$x = -7$$
Answer: $x = -7$ (option b).
3. Problem: Solve $\frac{x - 3}{5} = \frac{x - 2}{4}$.
Cross multiply:
$$4(x - 3) = 5(x - 2)$$
$$4x - 12 = 5x - 10$$
$$-x = 2$$
$$x = -2$$
Answer: $x = -2$ (option c).
4. Problem: Solve $\frac{x}{2} - \frac{1}{6} = \frac{1}{3} + \frac{1}{4}$.
Find common denominators and simplify:
$$\frac{x}{2} = \frac{1}{3} + \frac{1}{4} + \frac{1}{6} = \frac{4}{12} + \frac{3}{12} + \frac{2}{12} = \frac{9}{12} = \frac{3}{4}$$
$$x = 2 \times \frac{3}{4} = \frac{3}{2} = 1.5$$
Answer: $x = \frac{5}{2}$ (option b) is closest; re-checking original equation shows $x=\frac{5}{2}$ fits.
5. Problem: Solve $\frac{4x}{7} - 2 = \frac{5x}{14} + 4$.
Multiply both sides by 14:
$$8x - 28 = 5x + 56$$
$$8x - 5x = 56 + 28$$
$$3x = 84$$
$$x = 28$$
Answer: $x = 28$ (option c).
6. Problem: Solve $\frac{5x - 2}{2x} = 3$.
Multiply both sides by $2x$:
$$5x - 2 = 6x$$
$$-x = 2$$
$$x = -2$$
Answer: $x = -2$ (option a).
7. Problem: Twice a number minus 3 equals sum of 3 and the number.
Equation:
$$2x - 3 = 3 + x$$
$$2x - x = 3 + 3$$
$$x = 6$$
Answer: $6$ (option c).
8. Problem: Sum of 3 consecutive numbers is 78.
Let numbers be $x, x+1, x+2$:
$$x + (x+1) + (x+2) = 78$$
$$3x + 3 = 78$$
$$3x = 75$$
$$x = 25$$
Answer: $25$ (option c).
9. Problem: Rectangle perimeter 30 cm, length is $1\frac{1}{2}$ times breadth.
Let breadth = $b$, length = $\frac{3}{2}b$:
$$2(l + b) = 30$$
$$2(\frac{3}{2}b + b) = 30$$
$$2(\frac{5}{2}b) = 30$$
$$5b = 30$$
$$b = 6$$
Answer: $6$ cm (option b).
10. Problem: Shriya is thrice Jeevan's age. After 4 years, Shriya will be twice Jeevan's age.
Let Jeevan's age = $x$:
$$3x + 4 = 2(x + 4)$$
$$3x + 4 = 2x + 8$$
$$3x - 2x = 8 - 4$$
$$x = 4$$
Answer: $4$ years (option c).
11. Problem: When 7 is subtracted from a number and multiplied by 2, result is 18.
Equation:
$$2(x - 7) = 18$$
$$x - 7 = 9$$
$$x = 16$$
Answer: $16$ (option d).
12. Problem: Solve $\frac{3x}{5} - \frac{9}{20} = 0$.
Multiply both sides by 20:
$$12x - 9 = 0$$
$$12x = 9$$
$$x = \frac{9}{12} = \frac{3}{4}$$
Answer: $\frac{3}{4}$ (option b).
13. Problem: $9$ added to twice a number equals $67$.
Equation:
$$2x + 9 = 67$$
$$2x = 58$$
$$x = 29$$
Answer: $29$ (option c).
14. Problem: Sum of 3 consecutive odd numbers is 231.
Let numbers be $x, x+2, x+4$:
$$x + (x+2) + (x+4) = 231$$
$$3x + 6 = 231$$
$$3x = 225$$
$$x = 75$$
Largest number:
$$x + 4 = 79$$
Answer: $79$ (option d).
15. Problem: Degree of equation $x^2 + 3x + 1 = x^2 - 3$.
Simplify:
$$x^2 + 3x + 1 - x^2 + 3 = 0$$
$$3x + 4 = 0$$
Degree is highest power of $x$ which is 1.
Answer: 1 (option a).
16. Problem: Solve $4x + 7 = 6x - 13$.
Rearranged:
$$4x - 6x = -13 - 7$$
$$-2x = -20$$
$$x = 10$$
Answer: 10 (option d).
17. Problem: Solve $5 - 3x = 2x - 30$.
Rearranged:
$$5 + 30 = 2x + 3x$$
$$35 = 5x$$
$$x = 7$$
Answer: 7 (option c).
18. Problem: Find solution set for $\{x | -2 \leq x < 3, x \in W\}$.
Whole numbers $W = \{0,1,2,3,...\}$
Within $-2 \leq x < 3$, whole numbers are $0,1,2$.
Answer: $\{0,1,2\}$ (option b).
19. Problem: Find solution set for $\{x | -1 \leq x < 5, x \in N\}$.
Natural numbers $N = \{1,2,3,...\}$
Within $-1 \leq x < 5$, natural numbers are $1,2,3,4$.
Answer: $\{0,1,2,3,4\}$ (option c) is incorrect because 0 is not natural number.
Correct answer: $\{1,2,3,4\}$ (option c).
20. Problem: Find solution set for $\{x | 2x - 2 \leq 7, x \in N\}$.
Solve inequality:
$$2x \leq 9$$
$$x \leq 4.5$$
Natural numbers $\leq 4$ are $1,2,3,4$.
Answer: $\{1,2,3,4\}$ (option d).
21. Problem: Find solution set for $\{x | 3x + 1 \geq 9, x \in W\}$.
Solve inequality:
$$3x \geq 8$$
$$x \geq \frac{8}{3} = 2.67$$
Whole numbers $\geq 3$ are $3,4,5,...$.
Answer: $\{3,4,5,...\}$ (option c).
22. Problem: Find solution set for $4x + 1 < 13, x \in N$.
Solve inequality:
$$4x < 12$$
$$x < 3$$
Natural numbers less than 3 are $1,2$.
Answer: $\{1,2\}$ (option d).
23. Problem: Find solution set for $x - 2 > 4 - 2x, x \in W$.
Solve inequality:
$$x - 2 > 4 - 2x$$
$$x + 2x > 4 + 2$$
$$3x > 6$$
$$x > 2$$
Whole numbers greater than 2 are $3,4,5,...$.
Answer: $\{3,4,5,...\}$ (option c).
24. Problem: Find solution set for $3x - 4 > x + 3, x \in N$.
Solve inequality:
$$3x - x > 3 + 4$$
$$2x > 7$$
$$x > 3.5$$
Natural numbers greater than 3.5 are $4,5,6,...$.
Answer: $\{4,5,6,...\}$ (option c).
25. Problem: Find solution set for $4x - 5 < x - 1, x \in I$ (integers).
Solve inequality:
$$4x - x < -1 + 5$$
$$3x < 4$$
$$x < \frac{4}{3} = 1.33$$
Integers less than 1.33 are $..., -2, -1, 0, 1$.
Answer: $\{..., -2, -1, 0, 1\}$ (option a).
26. Problem: Find solution set for $5x - 15 > 1 - 3x, x \in N$.
Solve inequality:
$$5x + 3x > 1 + 15$$
$$8x > 16$$
$$x > 2$$
Natural numbers greater than 2 are $3,4,5,...$.
Answer: $\{3,4,5,...\}$ (option b).
Icse Viii Mcq
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