1. The problem is to identify coefficients $a$, $b$, and $c$ for each quadratic equation. 2. For $x^2 + x - 6 = 0$, rewrite the equation as is: $a=1$, $b=1$, $c=-6$. 3. For $x^2 - 7 = 5x$, rearrange to standard form: $x^2 - 5x - 7 = 0$. Thus, $a=1$, $b=-5$, $c=-7$. 4. For $x^2 = 10$, write as $x^2 - 10 = 0$. So, $a=1$, $b=0$, $c=-10$. 5. For $9x^2 = 4x - 1$, rewrite as $9x^2 - 4x + 1 = 0$, giving $a=9$, $b=-4$, $c=1$. 6. For $3m^2 + 9 = 6m$, rearranged as $3m^2 - 6m + 9 = 0$, so $a=3$, $b=-6$, $c=9$. 7. For $4t^2 = 12t$, write $4t^2 - 12t = 0$ or $4t^2 -12t + 0=0$, so $a=4$, $b=-12$, $c=0$. Summary: 1. $a=1$, $b=1$, $c=-6$ 2. $a=1$, $b=-5$, $c=-7$ 3. $a=1$, $b=0$, $c=-10$ 4. $a=9$, $b=-4$, $c=1$ 5. $a=3$, $b=-6$, $c=9$ 6. $a=4$, $b=-12$, $c=0$