1. **Problem Statement:** Convert each improper fraction into a mixed number. 2. **Formula and Explanation:** An improper fraction has a numerator larger than the denominator. To convert it to a mixed number, divide the numerator by the denominator: $$\text{Mixed number} = \text{Whole number} + \frac{\text{Remainder}}{\text{Denominator}}$$ 3. **Step-by-step Conversion:** (a) $\frac{6}{5}$: Divide 6 by 5. $$6 \div 5 = 1 \text{ remainder } 1$$ Mixed number: $$1 + \frac{1}{5} = 1 \frac{1}{5}$$ (b) $\frac{5}{4}$: Divide 5 by 4. $$5 \div 4 = 1 \text{ remainder } 1$$ Mixed number: $$1 + \frac{1}{4} = 1 \frac{1}{4}$$ (c) $\frac{3}{2}$: Divide 3 by 2. $$3 \div 2 = 1 \text{ remainder } 1$$ Mixed number: $$1 + \frac{1}{2} = 1 \frac{1}{2}$$ (d) $\frac{7}{4}$: Divide 7 by 4. $$7 \div 4 = 1 \text{ remainder } 3$$ Mixed number: $$1 + \frac{3}{4} = 1 \frac{3}{4}$$ (e) $\frac{11}{6}$: Divide 11 by 6. $$11 \div 6 = 1 \text{ remainder } 5$$ Mixed number: $$1 + \frac{5}{6} = 1 \frac{5}{6}$$ (f) $\frac{4}{3}$: Divide 4 by 3. $$4 \div 3 = 1 \text{ remainder } 1$$ Mixed number: $$1 + \frac{1}{3} = 1 \frac{1}{3}$$ (g) $\frac{11}{8}$: Divide 11 by 8. $$11 \div 8 = 1 \text{ remainder } 3$$ Mixed number: $$1 + \frac{3}{8} = 1 \frac{3}{8}$$ (h) $\frac{13}{10}$: Divide 13 by 10. $$13 \div 10 = 1 \text{ remainder } 3$$ Mixed number: $$1 + \frac{3}{10} = 1 \frac{3}{10}$$ 4. **Summary:** Each improper fraction is converted by dividing numerator by denominator to get the whole number and remainder, then writing the mixed number as whole number plus remainder over denominator.