1. **Problem 54:** Calculate how many more males will work in the industry next year if female engineers increase by 20% but males stay the same. - Given data for Engineering: Male = 156, Female = 101 (in thousands). - Female increase = 20% of 101 = $$0.20 \times 101 = 20.2$$ thousand. - Males stay the same, so no increase in males. - The question asks: "how many more males will work in the industry?" Since males stay the same, the increase in males is 0. **Answer:** 0 (none of the options match because males do not increase). 2. **Problem 55:** Find the ratio of total attendance of Year 9 to Year 10 in simplest form. - Total attendance Year 9 = 144 - Total attendance Year 10 = 148 - Ratio = $$144 : 148$$ - Simplify by dividing both by 4: $$\frac{144}{4} : \frac{148}{4} = 36 : 37$$ **Answer:** 36:37 (Option D) 3. **Problem 56:** Find the population on January 1, 2000, given it increased by 2% per year to reach 2,000,000 on December 31, 2003. - Let initial population be $$P$$. - Population grows by 2% per year for 4 years (2000 to end of 2003). - Growth formula: $$P \times (1.02)^4 = 2,000,000$$ - Calculate $$P = \frac{2,000,000}{(1.02)^4}$$ - Calculate $$ (1.02)^4 = 1.08243216$$ - So, $$P = \frac{2,000,000}{1.08243216} \approx 1,848,000$$ - Rounded to nearest thousand: 1,848,000 rounds to 1,848,000 (closest option 1,846,000) **Answer:** 1,846,000 (Option A)