1. Solve the inequality \(-3a - 1 \frac{1}{2} < -5 \frac{1}{4}\).
2. Solve the inequality \(\frac{m}{8} - 2 \frac{1}{2} > -4\).
3. Solve the inequality \(\frac{h}{2} + \frac{h}{3} - \frac{1}{2} \leq 5 \frac{1}{3}\).
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### Step 1: Solve \(-3a - 1 \frac{1}{2} < -5 \frac{1}{4}\)
1. Convert mixed numbers to improper fractions:
\(-3a - \frac{3}{2} < -\frac{21}{4}\)
2. Add \(\frac{3}{2}\) to both sides:
$$-3a - \frac{3}{2} + \frac{3}{2} < -\frac{21}{4} + \frac{3}{2}$$
$$-3a < -\frac{21}{4} + \frac{6}{4}$$
$$-3a < -\frac{15}{4}$$
3. Divide both sides by \(-3\), remembering to reverse the inequality sign because dividing by a negative number flips the inequality:
$$\frac{\cancel{-3}a}{\cancel{-3}} > \frac{ -\frac{15}{4} }{ -3 }$$
$$a > \frac{15}{12} = \frac{5}{4}$$
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### Step 2: Solve \(\frac{m}{8} - 2 \frac{1}{2} > -4\)
1. Convert mixed number to improper fraction:
$$\frac{m}{8} - \frac{5}{2} > -4$$
2. Add \(\frac{5}{2}\) to both sides:
$$\frac{m}{8} > -4 + \frac{5}{2}$$
Convert \(-4\) to \(-\frac{8}{2}\):
$$\frac{m}{8} > -\frac{8}{2} + \frac{5}{2} = -\frac{3}{2}$$
3. Multiply both sides by 8:
$$m > 8 \times -\frac{3}{2}$$
$$m > -12$$
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### Step 3: Solve \(\frac{h}{2} + \frac{h}{3} - \frac{1}{2} \leq 5 \frac{1}{3}\)
1. Convert mixed number to improper fraction:
$$\frac{h}{2} + \frac{h}{3} - \frac{1}{2} \leq \frac{16}{3}$$
2. Add \(\frac{1}{2}\) to both sides:
$$\frac{h}{2} + \frac{h}{3} \leq \frac{16}{3} + \frac{1}{2}$$
Find common denominator 6:
$$\frac{16}{3} = \frac{32}{6}, \quad \frac{1}{2} = \frac{3}{6}$$
So:
$$\frac{h}{2} + \frac{h}{3} \leq \frac{32}{6} + \frac{3}{6} = \frac{35}{6}$$
3. Find common denominator for \(\frac{h}{2} + \frac{h}{3}\):
$$\frac{3h}{6} + \frac{2h}{6} = \frac{5h}{6}$$
So:
$$\frac{5h}{6} \leq \frac{35}{6}$$
4. Multiply both sides by 6:
$$5h \leq 35$$
5. Divide both sides by 5:
$$h \leq 7$$
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### Final answers:
1. \(a > \frac{5}{4}\)
2. \(m > -12\)
3. \(h \leq 7\)
Inequalities 4 6 6E2Ddd
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