1. **Problem 24:** Solve the inequality $3[1 + (-2)] + e \leq \frac{2e}{3}$.
2. First, simplify inside the brackets:
$$3[1 + (-2)] = 3[-1] = -3$$
3. Substitute back:
$$-3 + e \leq \frac{2e}{3}$$
4. Add 3 to both sides:
$$\cancel{-3} + e + 3 \leq \frac{2e}{3} + 3$$
$$e \leq \frac{2e}{3} + 3$$
5. Subtract $\frac{2e}{3}$ from both sides:
$$e - \frac{2e}{3} \leq 3$$
$$\frac{3e}{3} - \frac{2e}{3} \leq 3$$
$$\frac{e}{3} \leq 3$$
6. Multiply both sides by 3:
$$e \leq 9$$
---
**Problem 25:** Solve $6s - 3 - 2s \geq 2s - 1.4$.
1. Simplify left side:
$$6s - 2s - 3 \geq 2s - 1.4$$
$$4s - 3 \geq 2s - 1.4$$
2. Add 3 to both sides:
$$4s - 3 + 3 \geq 2s - 1.4 + 3$$
$$4s \geq 2s + 1.6$$
3. Subtract $2s$ from both sides:
$$4s - 2s \geq 1.6$$
$$2s \geq 1.6$$
4. Divide both sides by 2:
$$\cancel{2}s / \cancel{2} \geq \frac{1.6}{2}$$
$$s \geq 0.8$$
---
**Problem 26:** Solve $9h - 3 \frac{1}{5} \geq 10h + \frac{12}{5}$.
1. Convert mixed number to improper fraction:
$$3 \frac{1}{5} = \frac{16}{5}$$
2. Rewrite inequality:
$$9h - \frac{16}{5} \geq 10h + \frac{12}{5}$$
3. Subtract $10h$ from both sides:
$$9h - 10h - \frac{16}{5} \geq \frac{12}{5}$$
$$-h - \frac{16}{5} \geq \frac{12}{5}$$
4. Add $\frac{16}{5}$ to both sides:
$$-h \geq \frac{12}{5} + \frac{16}{5}$$
$$-h \geq \frac{28}{5}$$
5. Multiply both sides by $-1$ and reverse inequality:
$$h \leq -\frac{28}{5}$$
---
**Problem 27:** Graph compound inequality $x > -3$ and $x \leq 1$.
- This means $x$ is greater than $-3$ (open circle) and less than or equal to $1$ (closed circle).
---
**Problem 28:** Graph compound inequality $x > 4$ or $x < -2$.
- This means $x$ is either greater than $4$ (open circle) or less than $-2$ (open circle).
---
**Problem 29:** Graph compound inequality $0 \leq x \leq 5$.
- This means $x$ is between $0$ and $5$ inclusive (closed circles at both ends).
---
**Problem 30:** Write compound inequality for graph: $-3 \geq n$ and $n \leq 1$.
- This is $n \leq -3$ and $n \leq 1$.
---
**Problem 31:** Write compound inequality for graph: $-4 \geq n$ and $n \leq 4$.
- This is $n \leq -4$ and $n \leq 4$.
---
**Problem 32:** Write compound inequality for graph: $n \leq -4$ or $7 \geq n$.
- This is $n \leq -4$ or $n \leq 7$.
---
**Problem 33:** Sum of two consecutive even numbers is greater than 66. Find least possible values.
1. Let first even number be $x$, second is $x+2$.
2. Inequality:
$$x + (x+2) > 66$$
$$2x + 2 > 66$$
3. Subtract 2:
$$2x > 64$$
4. Divide by 2:
$$x > 32$$
5. Least even integer greater than 32 is 34.
6. So numbers are 34 and 36.
---
**Problem 34:** Susan completed 3 times as many art projects as Molly. Together more than 12 projects. Find Molly's projects.
1. Let Molly's projects be $m$.
2. Susan's projects: $3m$.
3. Inequality:
$$m + 3m > 12$$
$$4m > 12$$
4. Divide by 4:
$$m > 3$$
5. Molly completed more than 3 projects.
---
**Problem 35:** Tony has 3 more than twice Peter's coins. Together fewer than 87 coins. Find Peter's coins.
1. Let Peter's coins be $p$.
2. Tony's coins: $2p + 3$.
3. Inequality:
$$p + (2p + 3) < 87$$
$$3p + 3 < 87$$
4. Subtract 3:
$$3p < 84$$
5. Divide by 3:
$$p < 28$$
6. Peter has fewer than 28 coins.
---
**Problem 36:** Sum of two consecutive odd numbers at most 32. Find greatest possible values.
1. Let first odd number be $x$, second $x+2$.
2. Inequality:
$$x + (x+2) \leq 32$$
$$2x + 2 \leq 32$$
3. Subtract 2:
$$2x \leq 30$$
4. Divide by 2:
$$x \leq 15$$
5. Greatest odd number less than or equal to 15 is 15.
6. Numbers are 15 and 17.
---
**Problem 37:** Of 184 parking places, fewer than 70 filled. How many not filled?
1. Filled places $< 70$.
2. Not filled $> 184 - 70 = 114$.
3. So more than 114 places not filled.
---
**Problem 38:** 60 more boys than girls attended picnic. At most 230 boys. Find girls.
1. Let girls be $g$.
2. Boys: $g + 60$.
3. Inequality:
$$g + 60 \leq 230$$
4. Subtract 60:
$$g \leq 170$$
5. At most 170 girls attended.
Inequalities And Word Problems Fe1F70
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.