1. **State the problem:** We need to find the inequalities describing the unshaded region on the graph. 2. **Identify the lines:** - Solid line passes through points $(-3,0)$ and $(0,6)$. - Dotted line passes through points $(-3,7)$ and $(7,-3)$. 3. **Find equations of the lines:** - For the solid line: Slope $m = \frac{6-0}{0-(-3)} = \frac{6}{3} = 2$ Equation using point-slope form: $y - 0 = 2(x + 3)$ Simplify: $y = 2x + 6$ - For the dotted line: Slope $m = \frac{-3-7}{7-(-3)} = \frac{-10}{10} = -1$ Equation using point-slope form: $y - 7 = -1(x + 3)$ Simplify: $y = -x + 4$ 4. **Determine inequalities based on shading:** - Solid line is solid and shaded below it, so unshaded region is above it: $$y > 2x + 6$$ - Dotted line is dotted and shaded above it, so unshaded region is below it: $$y < -x + 4$$ 5. **Final inequalities describing the unshaded region:** $$\boxed{y > 2x + 6 \quad \text{and} \quad y < -x + 4}$$