1. The problem asks to write down the two inequalities that describe the unshaded region on the graph. 2. First, find the equations of the two lines. - For the solid line passing through points (-2,0) and (4,7): The slope is $m=\frac{7-0}{4-(-2)}=\frac{7}{6}$. Using point-slope form with point (-2,0): $$y-0=\frac{7}{6}(x+2) \implies y=\frac{7}{6}x+\frac{7}{3}$$ - For the dotted line passing through points (0,5) and (5,0): The slope is $m=\frac{0-5}{5-0}=-1$. Using point-slope form with point (0,5): $$y-5=-1(x-0) \implies y=-x+5$$ 3. The shaded region is below the solid line and above the dotted line. - "Below the solid line" means: $$y \leq \frac{7}{6}x + \frac{7}{3}$$ - "Above the dotted line" means: $$y \geq -x + 5$$ 4. The unshaded region is the complement of the shaded region, so it is either above the solid line or below the dotted line. - Above the solid line: $$y > \frac{7}{6}x + \frac{7}{3}$$ - Below the dotted line: $$y < -x + 5$$ 5. Therefore, the two inequalities describing the unshaded region are: $$y > \frac{7}{6}x + \frac{7}{3}$$ and $$y < -x + 5$$