1. The problem is to graph the inequality $y + 3x > -2$. 2. First, rewrite the inequality in terms of $y$ to make it easier to graph: $$y > -3x - 2$$ 3. The boundary line is the equation: $$y = -3x - 2$$ This line divides the plane into two regions. 4. Since the inequality is strict ($>$), the boundary line is dashed, indicating points on the line are not included. 5. To determine which side to shade, pick a test point not on the line, for example $(0,0)$: $$0 > -3(0) - 2$$ $$0 > -2$$ This is true, so shade the region above the line. 6. The graph consists of a dashed line $y = -3x - 2$ and the region above it shaded. Final answer: Graph the dashed line $y = -3x - 2$ and shade the region above it where $y > -3x - 2$.