1. The problem asks to identify which inequality matches a graph with a line of slope $-\frac{3}{4}$ and y-intercept 3, where the line is solid and the shaded area is above the line. 2. The general form of the line is $y = -\frac{3}{4}x + 3$. 3. Important rules: - A solid line means the inequality includes equality ($\leq$ or $\geq$). - Shading above the line means $y$ is greater than or equal to the line ($y \geq$) or strictly greater ($y >$). 4. Since the line is solid and shading is above, the correct inequality is: $$y \geq -\frac{3}{4}x + 3$$ 5. The other options do not match because: - $y \leq -\frac{3}{4}x + 3$ shades below the line. - $y < -\frac{3}{4}x + 3$ is dashed and shades below. - $y > -\frac{3}{4}x + 3$ is dashed and shades above. Final answer: $$\boxed{y \geq -\frac{3}{4}x + 3}$$