1. The problem is to graph the inequality $2x - 5y > 3$. 2. Rewrite the inequality in slope-intercept form $y < \frac{2}{5}x - \frac{3}{5}$. 3. This represents the region below the line $y = \frac{2}{5}x - \frac{3}{5}$ (dashed line because of strict inequality). 1. The problem is to graph the inequality $3x - 7y \leq 4$. 2. Rewrite the inequality in slope-intercept form $y \geq \frac{3}{7}x - \frac{4}{7}$. 3. This represents the region above the line $y = \frac{3}{7}x - \frac{4}{7}$ (solid line because of \leq). 1. The problem is to graph the inequality $5x + 3y \geq 1$. 2. Rewrite the inequality in slope-intercept form $y \geq -\frac{5}{3}x + \frac{1}{3}$. 3. This represents the region above the line $y = -\frac{5}{3}x + \frac{1}{3}$ (solid line because of \geq). 1. The problem is to graph the inequality $x - 6y \geq 2$. 2. Rewrite the inequality in slope-intercept form $y \leq \frac{1}{6}x - \frac{1}{3}$. 3. This represents the region below the line $y = \frac{1}{6}x - \frac{1}{3}$ (solid line because of \geq rewritten as \leq for y). Each inequality is graphed as a line with the region shaded either above or below depending on the inequality sign.