Subjects algebra

Inequality Solve C55757

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1. **State the problem:** Solve the inequality $$6 \geq -\frac{8}{3} v$$ for $$v$$. 2. **Recall the rule:** When multiplying or dividing both sides of an inequality by a negative number, the inequality sign must be reversed. 3. **Isolate $$v$$:** Start with $$6 \geq -\frac{8}{3} v$$. Divide both sides by $$-\frac{8}{3}$$, which is negative, so reverse the inequality: $$\frac{6}{-\frac{8}{3}} \leq v$$ 4. **Simplify the division:** $$\frac{6}{-\frac{8}{3}} = 6 \times \frac{3}{-8} = \frac{18}{-8} = -\frac{9}{4}$$ So, $$v \geq -\frac{9}{4}$$ becomes $$v \leq -\frac{9}{4}$$ after reversing the inequality. 5. **Final answer:** $$\boxed{v \leq -\frac{9}{4}}$$ This means $$v$$ can be any number less than or equal to $$-2.25$$.