1. **State the problem:** Solve the inequality $$6 \geq -\frac{8}{3} v$$ for $$v$$.
2. **Recall the rule:** When multiplying or dividing both sides of an inequality by a negative number, the inequality sign must be reversed.
3. **Isolate $$v$$:**
Start with $$6 \geq -\frac{8}{3} v$$.
Divide both sides by $$-\frac{8}{3}$$, which is negative, so reverse the inequality:
$$\frac{6}{-\frac{8}{3}} \leq v$$
4. **Simplify the division:**
$$\frac{6}{-\frac{8}{3}} = 6 \times \frac{3}{-8} = \frac{18}{-8} = -\frac{9}{4}$$
So,
$$v \geq -\frac{9}{4}$$ becomes $$v \leq -\frac{9}{4}$$ after reversing the inequality.
5. **Final answer:**
$$\boxed{v \leq -\frac{9}{4}}$$
This means $$v$$ can be any number less than or equal to $$-2.25$$.
Inequality Solve C55757
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.