1. **State the problem:** Solve the inequality $$5h + 5(9h + 1) \leq 5h + 1 - 2$$ for $h$.
2. **Apply the distributive property:** Multiply $5$ by each term inside the parentheses:
$$5h + 5 \times 9h + 5 \times 1 \leq 5h + 1 - 2$$
which simplifies to
$$5h + 45h + 5 \leq 5h + 1 - 2$$
3. **Combine like terms on the left side:**
$$50h + 5 \leq 5h + (1 - 2)$$
$$50h + 5 \leq 5h - 1$$
4. **Subtract $5h$ from both sides to isolate $h$ terms on one side:**
$$50h - 5h + 5 \leq -1$$
$$45h + 5 \leq -1$$
5. **Subtract 5 from both sides:**
$$45h \leq -1 - 5$$
$$45h \leq -6$$
6. **Divide both sides by 45:**
Since 45 is positive, the inequality direction stays the same:
$$h \leq \frac{-6}{45}$$
7. **Simplify the fraction:**
$$h \leq \frac{-2}{15}$$
**Final answer:**
$$\boxed{h \leq -\frac{2}{15}}$$
Inequality Solve D6B535
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.