1. **State the problem:** Solve the inequality $$y + \frac{7}{8} > \frac{3}{4}$$. 2. **Formula and rules:** To isolate $y$, subtract $\frac{7}{8}$ from both sides of the inequality. When subtracting or adding the same number on both sides, the inequality direction remains the same. 3. **Subtract $\frac{7}{8}$ from both sides:** $$y + \frac{7}{8} - \frac{7}{8} > \frac{3}{4} - \frac{7}{8}$$ 4. **Simplify left side:** $$y > \frac{3}{4} - \frac{7}{8}$$ 5. **Find common denominator for right side:** The denominators are 4 and 8. The least common denominator is 8. 6. **Convert $\frac{3}{4}$ to eighths:** $$\frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8}$$ 7. **Subtract fractions:** $$\frac{6}{8} - \frac{7}{8} = \frac{6 - 7}{8} = \frac{-1}{8}$$ 8. **Final inequality:** $$y > -\frac{1}{8}$$ **Answer:** The solution to the inequality is $$y > -\frac{1}{8}$$.