1. **Stating the problem:**
We are given two conditions involving an integer $n$:
- $n > 5$
- $-1 < n + 3 \leq 5$
We need to find all possible integer values of $n$ that satisfy both conditions.
2. **Analyze the first condition:**
The first condition is straightforward:
$$n > 5$$
This means $n$ must be an integer greater than 5, so possible values are $6, 7, 8, \ldots$.
3. **Analyze the second condition:**
The second condition is:
$$-1 < n + 3 \leq 5$$
We can solve this compound inequality step-by-step.
First, subtract 3 from all parts:
$$-1 - 3 < n + 3 - 3 \leq 5 - 3$$
which simplifies to:
$$-4 < n \leq 2$$
Since $n$ is an integer, this means:
$$n \in \{-3, -2, -1, 0, 1, 2\}$$
4. **Combine both conditions:**
We want integers $n$ such that:
$$n > 5$$
and
$$-4 < n \leq 2$$
There is no integer $n$ that is simultaneously greater than 5 and less than or equal to 2.
5. **Conclusion:**
No integer values of $n$ satisfy both conditions simultaneously.
**Final answer:**
There are no possible values of $n$ that satisfy both $n > 5$ and $-1 < n + 3 \leq 5$.
Integer Inequalities
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