1. **Problem statement:** Find the x- and y-intercepts of the polynomial function $$f(x) = x^2(x - 5)(x^2 + 2)$$.
2. **Recall definitions:**
- The **x-intercepts** are the values of $x$ where $f(x) = 0$.
- The **y-intercept** is the value of $f(0)$.
3. **Find x-intercepts:**
Set $$f(x) = 0$$:
$$x^2(x - 5)(x^2 + 2) = 0$$
4. **Solve each factor:**
- $$x^2 = 0 \implies x = 0$$
- $$x - 5 = 0 \implies x = 5$$
- $$x^2 + 2 = 0 \implies x^2 = -2$$ which has no real solutions.
5. **Therefore, the real x-intercepts are:**
$$x = 0, 5$$
6. **Find y-intercept:**
Evaluate $$f(0)$$:
$$f(0) = 0^2(0 - 5)(0^2 + 2) = 0$$
7. **Summary:**
- x-intercepts: $$0, 5$$
- y-intercept: $$0$$
Intercepts 93Cc90
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