1. **Problem:** Find the X- and Y-intercepts of the equation $$\frac{x}{2} + \frac{y}{3} = 1$$. 2. **Formula and rules:** - X-intercept is found by setting $$y=0$$ and solving for $$x$$. - Y-intercept is found by setting $$x=0$$ and solving for $$y$$. 3. **Find X-intercept:** Set $$y=0$$ in the equation: $$\frac{x}{2} + \frac{0}{3} = 1 \implies \frac{x}{2} = 1$$ Multiply both sides by 2: $$\cancel{2} \times \frac{x}{\cancel{2}} = 1 \times 2 \implies x = 2$$ 4. **Find Y-intercept:** Set $$x=0$$ in the equation: $$\frac{0}{2} + \frac{y}{3} = 1 \implies \frac{y}{3} = 1$$ Multiply both sides by 3: $$\cancel{3} \times \frac{y}{\cancel{3}} = 1 \times 3 \implies y = 3$$ 5. **Answer:** - X-intercept is at the point $$(2, 0)$$. - Y-intercept is at the point $$(0, 3)$$.